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8x^2-9=82
We move all terms to the left:
8x^2-9-(82)=0
We add all the numbers together, and all the variables
8x^2-91=0
a = 8; b = 0; c = -91;
Δ = b2-4ac
Δ = 02-4·8·(-91)
Δ = 2912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2912}=\sqrt{16*182}=\sqrt{16}*\sqrt{182}=4\sqrt{182}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{182}}{2*8}=\frac{0-4\sqrt{182}}{16} =-\frac{4\sqrt{182}}{16} =-\frac{\sqrt{182}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{182}}{2*8}=\frac{0+4\sqrt{182}}{16} =\frac{4\sqrt{182}}{16} =\frac{\sqrt{182}}{4} $
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